z^2-500z=0

Solution for z^2-500z=0 equation:

z^2-500z=0

a = 1; b = -500; c = 0;
Δ = b2-4ac
Δ = -5002-4·1·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-500}{2*1}=\frac{0}{2}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+500}{2*1}=\frac{1000}{2}
=500
$